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If the two forces shown in the diagram below are applied to the 2 kg ball, then what is the resulting acceleration of the ball? 2kg F_(2)=8.0N Frictionless Surface F_(1)=2.0N a 5.0m/s^2 to the left b 3.0m/s^2 to the right 5.0m/s^2 to the right d 3.0 m/s?to the left

Question

If the two forces shown in the diagram below are applied to the 2
kg ball, then what is the resulting acceleration of the ball?
2kg F_(2)=8.0N
Frictionless Surface
F_(1)=2.0N
a 5.0m/s^2 to the left
b 3.0m/s^2 to the right
5.0m/s^2 to the right
d 3.0 m/s?to the left

If the two forces shown in the diagram below are applied to the 2 kg ball, then what is the resulting acceleration of the ball? 2kg F_(2)=8.0N Frictionless Surface F_(1)=2.0N a 5.0m/s^2 to the left b 3.0m/s^2 to the right 5.0m/s^2 to the right d 3.0 m/s?to the left

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QueenElite · Tutor for 8 years

Answer

C. \( 5.0 \, m/s^2 \) to the right

Explain

To determine the resulting acceleration, we need to apply Newton's Second Law of Motion, \( F = ma \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration. Without the diagram, we assume the net force direction and magnitude based on the given options.
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