Liquid A has a density of 0.7g/cm^3 Liquid B has a density of 1.6g/cm^3 140 g of liquid A and 128 g of liquid B are mixed to make liquid C. Work out the density of liquid C.

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Liquid A has a density of 0.7g/cm^3 Liquid B has a density of 1.6g/cm^3 140 g of liquid A and 128 g of liquid B are mixed to make liquid C. Work out the density of liquid C.

Answer 1

Calculating the volumes from Step 1: - \( \frac{140g}{0.7g/cm^{3}} = 200 cm^{3}\) for Liquid A and - \(\frac{128g}{1.6g/cm^{3}} = 80 cm^{3}\) for Liquid B. For Step 2: Sum these volumes, 200 cm^{3} and 80 cm^{3} to make \(280 ~ cm^{3}\) this is the total volume for liquid C. Deducing the Density of the mixture Liquid C from Step 3: ### \(\frac{140g (for ~ A) + 128g (for ~ B)}{280 cm^{3}} = 0.96 ~ g/cm^{3} \) Thus, the density of liquid \( C \) is \( 0.96 ~ g/cm^{3} \).

Answer 2

## Step 1: First, find the volume of each liquid. The volume of a liquid can be calculated by the formula 'mass [g] / density [g/cm³]'. ### \(\frac{mass ~ of ~ liquid ~ A}{density ~ of ~ liquid ~ A} = \frac{140g}{0.7g/cm^{3}} \) ### \(\frac{mass ~ of ~ liquid ~ B}{density ~ of ~ liquid ~ B} = \frac{128g}{1.6g/cm^{3}} \) ## Step 2: Calculate the total volume (for liquid C), which is equal to \(Volume ~ of ~ liquid ~ A ~ in ~ cm^{3} + Volume ~ of ~ liquid ~ B ~ in ~ cm^{3} \). ## Step 3: The density of the mixed solution (liquid C) is found by taking the total mass which is \(Mass ~ of ~ liquid ~ A ~ (140g) + Mass ~ of ~ liquid ~ B ~ (128g)\) and dividing it by total the volume which is \(Volume ~ of ~ liquid ~ A ~ in ~ cm^{3} + Volume ~ of ~ liquid ~ B ~ in ~ cm^{3}\), derived in the steps 1 and 2 respectively. ### Defining the Density ~ formula: \(Density = \frac{Total ~ Mass}{Total ~ Volume} \)

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Liquid A has a density of 0.7g/cm^3 Liquid B has a density of 1.6g/cm^3 140 g of liquid A and 128 g of liquid B are mixed to make liquid C. Work out the density of liquid C.

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