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__ Q24. A cyclist has a mass of 64 kg. (i) The cyclist rides from a flat road to the top of a hill. The top of the hill is 24 m above the flat road. Calculate the gain in gravitational potential energy. Delta GPE of the cyclist. Use g=10N/kg Use the equation Delta GPE=mtimes gtimes Delta h gain in gravitational potential energy = __

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Q24.
A cyclist has a mass of 64 kg.
(i) The cyclist rides from a flat road to the top of a hill.
The top of the hill is 24 m above the flat road.
Calculate the gain in gravitational potential energy.
Delta GPE of the cyclist.
Use g=10N/kg
Use the equation
Delta GPE=mtimes gtimes Delta h
gain in gravitational potential energy =
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__ Q24. A cyclist has a mass of 64 kg. (i) The cyclist rides from a flat road to the top of a hill. The top of the hill is 24 m above the flat road. Calculate the gain in gravitational potential energy. Delta GPE of the cyclist. Use g=10N/kg Use the equation Delta GPE=mtimes gtimes Delta h gain in gravitational potential energy = __

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XavierProfessional · Tutor for 6 years

Answer

\(\triangle GPE = 15360 \, \mathrm{J}\)

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## Step 1:<br />Identify the given values:<br />- Mass of the cyclist, \(m = 64 \, \mathrm{kg}\)<br />- Gravitational field strength, \(g = 10 \, \mathrm{N/kg}\)<br />- Height gain, \(\Delta h = 24 \, \mathrm{m}\)<br /><br />## Step 2:<br />Write down the formula for gravitational potential energy:<br />### \[\triangle GPE = m \times g \times \Delta h\]<br /><br />## Step 3:<br />Substitute the given values into the formula:<br />### \[\triangle GPE = 64 \, \mathrm{kg} \times 10 \, \mathrm{N/kg} \times 24 \, \mathrm{m}\]<br /><br />## Step 4:<br />Perform the multiplication:<br />### \[\triangle GPE = 64 \times 10 \times 24 = 15360 \, \mathrm{J}\]<br /><br />## Step 5:<br />Verify the calculations to ensure accuracy:<br />### \[64 \times 10 = 640\]<br />### \[640 \times 24 = 15360\]
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