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At a soccer practice, the players run sprints. They start at the goal,run 10 m toward the center of the field and then run back to the goal. Then they run 20 m toward the center of the field and back to the goal.Finally they run 30 m toward the center of the field, turn around, and run back to the goal again. One player times herself to try and beat her personal best time . She runs the first 10 min 2.5 s and gets back to the goal in 2.8 s. Then she runs the 20-m sprint in 5.7 s and gets back to the goal in 6.7 s. She runs the final 30-m sprint in 12 s and gets back to the goal in 15 s. What was her average speed for the entire exercise? 2.7m/s 0m/s 2.5m/s 3.0m/s

Question

At a soccer practice, the players run sprints. They start at the goal,run 10 m toward the center of the field and then run back to the goal. Then they run 20 m toward the center of the field and back to the goal.Finally they run 30 m toward the center of the field, turn around, and run back to the goal again. One player times herself to try and beat her personal best time . She runs the first 10 min 2.5 s and gets back to the goal in 2.8 s. Then she runs the 20-m sprint in 5.7 s and gets back to the goal in 6.7 s. She runs the final 30-m sprint in 12 s and gets back to the goal in 15 s. What was her average speed for the entire exercise? 2.7m/s 0m/s 2.5m/s 3.0m/s

At a soccer practice, the players run sprints. They start at the goal,run 10 m toward the center of the field and then run back to the goal. Then they run 20 m toward the center of the field and back to the goal.Finally they run 30 m toward the center of the field, turn around, and run back to the goal again. One player times herself to try and beat her personal best time . She runs the first 10 min 2.5 s and gets back to the goal in 2.8 s. Then she runs the 20-m sprint in 5.7 s and gets back to the goal in 6.7 s. She runs the final 30-m sprint in 12 s and gets back to the goal in 15 s. What was her average speed for the entire exercise? 2.7m/s 0m/s 2.5m/s 3.0m/s

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KeeganProfessional · Tutor for 6 years

Answer

\(2.7 \text{ m/s}\)

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## Step 1: To find the average speed, we need to divide the total distance by the total time taken.<br />## Step 2: Calculate the total distance run by the player.<br />### For the first sprint: \(10 \text{ m} \times 2 = 20 \text{ m}\)<br />### For the second sprint: \(20 \text{ m} \times 2 = 40 \text{ m}\)<br />### For the third sprint: \(30 \text{ m} \times 2 = 60 \text{ m}\)<br />### Total distance: \(20 \text{ m} + 40 \text{ m} + 60 \text{ m} = 120 \text{ m}\)<br />## Step 3: Calculate the total time taken by the player.<br />### For the first sprint: \(2.5 \text{ s} + 2.8 \text{ s} = 5.3 \text{ s}\)<br />### For the second sprint: \(5.7 \text{ s} + 6.7 \text{ s} = 12.4 \text{ s}\)<br />### For the third sprint: \(12 \text{ s} + 15 \text{ s} = 27 \text{ s}\)<br />### Total time: \(5.3 \text{ s} + 12.4 \text{ s} + 27 \text{ s} = 44.7 \text{ s}\)<br />## Step 4: The average speed is given by:<br />### \(\text{Average speed} = \frac{\text{Total distance}}{\text{Total time}}\)<br />## Step 5: Plugging in the values we have:<br />### \(\text{Average speed} = \frac{120 \text{ m}}{44.7 \text{ s}} \approx 2.68 \text{ m/s}\)<br />## Step 6: From the options provided, the closest value to \(2.68 \text{ m/s}\) is option \(2.7 \text{ m/s}\).
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