Home
/
Physics
/
What is the resistance of a 30 m length of 2.5mm^2 copper conductor if the resistivity of copper is 0.0178mu Omega /m a 0.01Omega 0.81Omega b 0.21Omega d 421Omega

Question

What is the resistance of a 30 m length of 2.5mm^2 copper conductor if the resistivity of copper is
0.0178mu Omega /m
a
0.01Omega 
0.81Omega 
b 0.21Omega 
d 421Omega

What is the resistance of a 30 m length of 2.5mm^2 copper conductor if the resistivity of copper is 0.0178mu Omega /m a 0.01Omega 0.81Omega b 0.21Omega d 421Omega

expert verifiedVerification of experts

Answer

4.2303 Voting
avatar
ZoeProfessional · Tutor for 6 years

Answer

\[ 0.21 \Omega \]

Explain

## Step 1:<br />The resistance \( R \) of a wire could be figured out by the formula \( R = \frac{\rho L}{A} \), where \( \rho \) is the resistivity of the metal (for copper it's around \( 0.0178 \times 10^{-6} \Omega.m \)), \( L \) stands for the length, and \( A \) is the cross-sectional surface of the wire which for this case is directly given.<br /><br />## Step 2:<br />Now, substituting the given values we have taken into concern:<br /><br />### \( R = \frac{0.0178 \times 10^{-6} \times 30}{2.5 \times 10^{-6}} \). <br /><br />## Step 3:<br />Upon simplifying it we could compute that <br /><br />### \( R \approx 0.21 \Omega \)
Click to rate:

Hot Questions

More x