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Calculate the energy to vaporize 1.85kg of water. Latent heat of vaporisation of weter=2260(kJ/kg) Add any workings here Energy=underline ( )kJ

Question

Calculate the energy to vaporize 1.85kg of water.
Latent heat of vaporisation of weter=2260(kJ/kg)
Add any workings here
Energy=underline ( )kJ

Calculate the energy to vaporize 1.85kg of water. Latent heat of vaporisation of weter=2260(kJ/kg) Add any workings here Energy=underline ( )kJ

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TheaVeteran · Tutor for 11 years

Answer

= 4181 kJ .

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Like the previous example, this question is based on the principles of thermal physics and requires us to calculate the amount of heat, or energy, necessary to convert a specified amount of water from a liquid state to a gaseous state - that is, to vaporize it. The formula we'll employ for this calculation is the same as in the previous question, Q = mL: <br /> - Q is the total amount of heat added or removed <br /> - m is the the mass of the substance involved in the phase change <br /> - L is the latent heat of vaporization, which describes the heat per unit mass needed to convert a substance from a liquid state to a gaseous state without altering the temperature <br /> We have everything we need for the computation because we were given specific quantities:<br /> - m is specified as 1.85kg <br /> - L is specified as being 2260 kJ per kg <br /> As was the case in the previous example, the units of measurement for mass (kg) and latent heat (kJ/kg) are consistent, which allows us to plug in the quantities and make the calculation,: <br /><br />Applying the formala would be, Q= mL<br />subsitute m = 1.85 kg and L = 2260 kJ/kg, we can calculate: <br /><br />Q = (1.85kg)*(2260kJ/kg)
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