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The dingram shows a block of metal on horizontal ground. pressure=(force)/(area) The base of the block of metal is a rectangle 20cm by xcm. The block exerts a force of 1500 newtons on the ground. The pressure on the ground is 3newtons/cm^2 Work out the value of x.

Question

The dingram shows a block of metal on horizontal ground.
pressure=(force)/(area)
The base of the block of metal is a rectangle 20cm by xcm.
The block exerts a force of 1500 newtons on the ground.
The pressure on the ground is 3newtons/cm^2
Work out the value of x.

The dingram shows a block of metal on horizontal ground. pressure=(force)/(area) The base of the block of metal is a rectangle 20cm by xcm. The block exerts a force of 1500 newtons on the ground. The pressure on the ground is 3newtons/cm^2 Work out the value of x.

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AlannahElite · Tutor for 8 years

Answer

\(x = 25\) cm

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## Step 1: Understand the problem<br />The problem involves finding the value of \(x\), which is one of the dimensions of the base of the block of metal. We know the pressure exerted by the block, the force exerted by the block, and one of the dimensions of the base of the block. We can use the formula for pressure to find the missing dimension.<br /><br />## Step 2: Setup the pressure formula<br />The formula for pressure is given by:<br /><br />### \(Pressure = \frac{Force}{Area}\)<br /><br />The area of the base of the block is a rectangle, so it is calculated as the product of its length and width. In this case, the length is 20 cm and the width is \(x\) cm. Therefore, the area is \(20x\) cm².<br /><br />## Step 3: Substitute the known values into the formula<br />We know that the pressure is 3 N/cm² and the force is 1500 N. Substituting these values into the formula, we get:<br /><br />### \(3 = \frac{1500}{20x}\)<br /><br />## Step 4: Solve for \(x\)<br />To solve for \(x\), we first multiply both sides of the equation by \(20x\) to get rid of the denominator on the right side. This gives us:<br /><br />### \(60x = 1500\)<br /><br />Then, we divide both sides of the equation by 60 to solve for \(x\):<br /><br />### \(x = \frac{1500}{60}\)
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