Home
/
Physics
/
(e) The acceleration of the apple is 9.8 mathrm(~m) / mathrm(s)^2 The velocity of the apple changes from 0 to 4.9 mathrm(~m) / mathrm(s) Calculate the time taken for the apple to fall to the ground. Use the equation: [ (1+4.4)/(9.8)=0,5 ]

Question

(e) The acceleration of the apple is 9.8 mathrm(~m) / mathrm(s)^2 
The velocity of the apple changes from 0 to 4.9 mathrm(~m) / mathrm(s) 
Calculate the time taken for the apple to fall to the ground.
Use the equation:
[
(1+4.4)/(9.8)=0,5
]

(e) The acceleration of the apple is 9.8 mathrm(~m) / mathrm(s)^2 The velocity of the apple changes from 0 to 4.9 mathrm(~m) / mathrm(s) Calculate the time taken for the apple to fall to the ground. Use the equation: [ (1+4.4)/(9.8)=0,5 ]

expert verifiedVerification of experts

Answer

4.7203 Voting
avatar
CharlotteMaster · Tutor for 5 years

Answer

The time taken for the apple to fall to the ground is approximately \( 0.5 \) seconds.

Explain

## Step1:<br />First, we identify the given values from the problem. The initial velocity (vi) of the apple is 0 m/s, the final velocity (vf) is 4.9 m/s, and the acceleration (a) is 9.8 m/s².<br /><br />## Step2:<br />We use the given formula to calculate the time taken for the apple to fall to the ground. The formula is:<br /><br />### \( \text{time taken} = \frac{\text{change in velocity}}{\text{acceleration}} \)<br /><br />The change in velocity is the final velocity minus the initial velocity. In this case, it is 4.9 m/s - 0 m/s = 4.9 m/s.<br /><br />## Step3:<br />Substituting the values into the formula, we get:<br /><br />### \( \text{time taken} = \frac{4.9 \, \text{m/s}}{9.8 \, \text{m/s}^2} \)
Click to rate:

Hot Questions

More x