26) What is the total combined resistance of the resistors show in the figure below? (L4.5) a) 35 Ohms b) 11.6 Ohms c) 2.9 Ohms d) 4.5 Ohms

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26) What is the total combined resistance of the resistors show in the figure below? (L4.5) a) 35 Ohms b) 11.6 Ohms c) 2.9 Ohms d) 4.5 Ohms

Answer 1

Unfortunately, there's no figure provided in your question. However, I can walk you through the process of calculating total resistance, both in series and in parallel. 1. If the resistors are arranged in series, the total resistance would simply be the sum of all resistance. In your previously mentioned example with 10 Ohm resistors, since there were only 2 and they were arranged in series, you'd add 10 Ohm and 10 Ohm, coming to a total of 20 Ohms. 2. When resistors are arranged in parallel, the calculation for total resistance becomes slightly more nuanced. This resistance can be calculated by the formula: ### \(\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2}+ ... +\frac{1}{R_n} \). Here \(R_1:\) is the first resistor, \(R_2:\) is the second resistor and \(R_n:\) is the nth resistor. You would first calculate each individual inverse resistor's value and then add them up to get the total inverse resistance value. To get to the total resistance, you would then take the total inverse you received from adding the individual inverses, and find the reciprocal of this value. I hope this sheds light on possible approach to solve such questions. Only if you could provide the figure, then I can perform specific calculations associated to this problem.

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26) What is the total combined resistance of the resistors show in the figure below? (L4.5) a) 35 Ohms b) 11.6 Ohms c) 2.9 Ohms d) 4.5 Ohms

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