21 ) A 5 Ohm resist or and a 7,Ohm resis tor are wired in se ries and hm connecte stor and to supply.at 15 the powel dissipate and the 7 Ohr n resist or? (1) 52 Watts b) 57 W atts c) 89 Watts d) 30 Watts (L4.5

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21 ) A 5 Ohm resist or and a 7,Ohm resis tor are wired in se ries and hm connecte stor and to supply.at 15 the powel dissipate and the 7 Ohr n resist or? (1) 52 Watts b) 57 W atts c) 89 Watts d) 30 Watts (L4.5

Answer 1

d) 30 Watts

Answer 2

## Step1: In this question, there are two resistors wired in series to a 25 volt supply. Since they are in series, the total resistance (R_T) of the circuit is the sum of the two resistances. So, we calculate, ### \(R_T = R_1 + R_2 = 5\, \Omega + 7\, \Omega = 12\, \Omega \) ## Step2: With a total resistance and voltage (V) known, we use Ohm’s law (I = V/R) to calculate the current in the circuit. ### \(I = \frac{V}{R_T} = \frac{25V}{12 \Omega} = 2.08 A \approx 2.1 A\) Since the resistors are wired in series, the current that flows in them is the same. ## Step3: The power (P) dissipated by a resistor can be computed using the formula \(P = I^2 \times R\). Substituting the current (\(I = 2.1 A\)) and resistance (\(R = 7 \Omega\)) into this formula gives us the power dissipated by the 7 Ohm resistor. ### \(P = (2.1 A)^2 \times 7 \Omega = 30.1 W \approx 30 W\) when rounded to a proper significant figure.

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21 ) A 5 Ohm resist or and a 7,Ohm resis tor are wired in se ries and hm connecte stor and to supply.at 15 the powel dissipate and the 7 Ohr n resist or? (1) 52 Watts b) 57 W atts c) 89 Watts d) 30 Watts (L4.5

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