A conductor measuring 50 m in length has a resistance of 0.4Omega What would be its resistance if its length is increased to 100 m? a 0.2Omega b 0.4Omega C 0.6Omega d 0.8Omega square

Question

Question

A conductor measuring 50 m in length has a resistance of 0.4Omega What would be its resistance if its length is increased to 100 m? a 0.2Omega b 0.4Omega C 0.6Omega d 0.8Omega square

Answer 1

\( d = 0.8 \) ohms

Answer 2

## Step1: As explained in the given example, the resistance of a conductor made of the same material is directly proportional to the length of the aforementioned conductor. This directly proportional relation establishes that the ratio of length to resistance corresponding to the 50 meter length (50m/0.4Ω) needs to be identical to the ratio for the 100 meter length conductor (100m/x). Here, x is the unidentified resistance that we have targeted to resolve. ## Step2: Replacing the given variables in to the proportion i.e., \( \frac{ \text{Length_1} }{ \text{Resistance_1} } = \frac{ \text{Length_2} }{ \text{Resistance_2} } \), gives us \( \frac{ 50 }{ 0.4 } = \frac{ 100 }{ x } \). This can be further written as \( x=\frac{(0.4*100)}{50} \). ## Step3: Evaluate \( x = \frac{ 0.4*100 }{ 50 } \) ### Step4: Ordering the count in step 3: First, calculate the multiplication: 0.4*100 = 40. Then, calculate the division: \( x = \frac{ 40 }{ 50 } = 0.8 \).

Question

A conductor measuring 50 m in length has a resistance of 0.4Omega What would be its resistance if its length is increased to 100 m? a 0.2Omega b 0.4Omega C 0.6Omega d 0.8Omega square

Answer

Answer

Explain

Hot Questions