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Q2. A teacher used a Geiger-Muller tube and counter to measure the number of counts in 60 seconds for a radioactive rock. (a) The counter recorded 819 counts in 60 seconds. The background radiation count rate was 0.30 counts per second. Calculate the count rate for the rock. __ Countrate=1335persecond (b) ) A householder is worried about the radiation emitted by the granite worktop in his kitchen. 1 kg of granite has an activity of 1250 Bq. The kitchen worktop has a mass of 180 kg. Calculate the activity of the kitchen worktop in Bq. __

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Q2.
A teacher used a Geiger-Muller tube and counter to measure the number of counts in 60
seconds for a radioactive rock.
(a) The counter recorded 819 counts in 60 seconds. The background radiation count
rate was 0.30 counts per second.
Calculate the count rate for the rock.
__
Countrate=1335persecond
(b) ) A householder is worried about the radiation emitted by the granite worktop in his
kitchen.
1 kg of granite has an activity of 1250 Bq. The kitchen worktop has a mass of
180 kg.
Calculate the activity of the kitchen worktop in Bq.
__

Q2. A teacher used a Geiger-Muller tube and counter to measure the number of counts in 60 seconds for a radioactive rock. (a) The counter recorded 819 counts in 60 seconds. The background radiation count rate was 0.30 counts per second. Calculate the count rate for the rock. __ Countrate=1335persecond (b) ) A householder is worried about the radiation emitted by the granite worktop in his kitchen. 1 kg of granite has an activity of 1250 Bq. The kitchen worktop has a mass of 180 kg. Calculate the activity of the kitchen worktop in Bq. __

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TrevorElite · Tutor for 8 years

Answer

## Part (a):<br />- Background radiation over 60 seconds = \(0.30 \times 60 = 18\) counts.<br />- Net counts = \(819 - 18 = 801\) counts.<br />- Count rate = \(\frac{801}{60} = 13.35\) counts per second.<br /><br />## Part (b):<br />- Activity = \(1250 \times 180 = 225000\) Bq.

Explain

## Part (a):<br />### Step 1: Identify the total counts and time.<br />- Total counts recorded: 819 in 60 seconds.<br />- Background radiation: 0.30 counts per second.<br /><br />### Step 2: Calculate the net count rate for the rock.<br />- Subtract the background radiation from the total counts to get the net counts.<br />- Background radiation over 60 seconds = \(0.30 \times 60\).<br /><br />### Step 3: Use the formula for count rate.<br />- **\(\mathbf{Count\ rate = \frac{Net\ counts}{Time}}\)**.<br /><br />## Part (b):<br />### Step 1: Identify given values.<br />- Activity of 1 kg of granite: 1250 Bq.<br />- Mass of the kitchen worktop: 180 kg.<br /><br />### Step 2: Calculate the total activity of the worktop.<br />- **\(\mathbf{Activity = 1250 \times 180}\)**.
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