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The trolley is a seat suspended from wheels which can roll along the zip wire. (d) When the person reaches the end of the zip wire, the person gets off the trolley. The block falls downwards pulling the trolley back to the top of the zip wire. maximum speed of block=4.8m/s mass of block=2.5kg Calculate the maximum kinetic energy of the block. Use the equation: kinetic energy=0.5times masstimes (speed)^2 __

Question

The trolley is a seat suspended from wheels which can roll along the zip wire.
(d) When the person reaches the end of the zip wire, the person gets off the trolley.
The block falls downwards pulling the trolley back to the top of the zip wire.
maximum speed of block=4.8m/s
mass of block=2.5kg
Calculate the maximum kinetic energy of the block.
Use the equation:
kinetic energy=0.5times masstimes (speed)^2
__

The trolley is a seat suspended from wheels which can roll along the zip wire. (d) When the person reaches the end of the zip wire, the person gets off the trolley. The block falls downwards pulling the trolley back to the top of the zip wire. maximum speed of block=4.8m/s mass of block=2.5kg Calculate the maximum kinetic energy of the block. Use the equation: kinetic energy=0.5times masstimes (speed)^2 __

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HaydenElite · Tutor for 8 years

Answer

\(28.8 \, \mathrm{J}\)

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## Step 1: Identify the given values.<br />- Maximum speed of the block, \(v = 4.8 \, \mathrm{m/s}\)<br />- Mass of the block, \(m = 2.5 \, \mathrm{kg}\)<br /><br />## Step 2: Write down the formula for kinetic energy.<br />### \[\text{Kinetic Energy} = 0.5 \times \text{mass} \times (\text{speed})^2\]<br /><br />## Step 3: Substitute the given values into the formula.<br />### \[\text{Kinetic Energy} = 0.5 \times 2.5 \, \mathrm{kg} \times (4.8 \, \mathrm{m/s})^2\]<br /><br />## Step 4: Perform the calculation.<br />### \[\text{Kinetic Energy} = 0.5 \times 2.5 \times 23.04\]<br />### \[\text{Kinetic Energy} = 0.5 \times 57.6\]<br />### \[\text{Kinetic Energy} = 28.8 \, \mathrm{J}\]
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