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A boy of 400 N weight 3m from the pivot of a see-saw will be balanced by __ a girl of 300 N at 4m a bag of sand (100 N)at 5m a boy of 400 N at 4m a man of 800 N at 2m

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A boy of 400 N weight 3m from the pivot of a see-saw will be balanced by __ a girl of 300 N at 4m a bag of sand (100 N)at 5m a boy of 400 N at 4m a man of 800 N at 2m

A boy of 400 N weight 3m from the pivot of a see-saw will be balanced by __ a girl of 300 N at 4m a bag of sand (100 N)at 5m a boy of 400 N at 4m a man of 800 N at 2m

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JulianProfessional · Tutor for 6 years

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### A. a girl of \(300 \mathrm{~N}\) at \(4 \mathrm{~m}\)

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## Step 1: Understand the Problem<br />### We need to determine which option balances the see-saw when a boy of \(400 \mathrm{~N}\) is \(3 \mathrm{~m}\) from the pivot.<br />## Step 2: Apply the Torque Equilibrium Condition<br />### The torque produced by the boy is \(400 \mathrm{~N} \times 3 \mathrm{~m} = 1200 \mathrm{~Nm}\). We need to find which option also produces \(1200 \mathrm{~Nm}\) of torque.<br />## Step 3: Calculate Torque for Each Option<br />### Option 1: \(300 \mathrm{~N} \times 4 \mathrm{~m} = 1200 \mathrm{~Nm}\)<br />### Option 2: \(100 \mathrm{~N} \times 5 \mathrm{~m} = 500 \mathrm{~Nm}\)<br />### Option 3: \(400 \mathrm{~N} \times 4 \mathrm{~m} = 1600 \mathrm{~Nm}\)<br />### Option 4: \(800 \mathrm{~N} \times 2 \mathrm{~m} = 1600 \mathrm{~Nm}\)
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