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A soccer ball is kicked at an angle of 30^circ If the ball requires 1 second to reach the goal, what is its initial velocity? 10m/s 0.5m/s 20m/s 5m/s

Question

A soccer ball is kicked at an angle of 30^circ 
If the ball requires 1 second to reach the goal, what is its
initial velocity?
10m/s
0.5m/s
20m/s
5m/s

A soccer ball is kicked at an angle of 30^circ If the ball requires 1 second to reach the goal, what is its initial velocity? 10m/s 0.5m/s 20m/s 5m/s

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IlonaProfessional · Tutor for 6 years

Answer

### $20 m/s$

Explain

## Step 1: Identify known quantities and the target<br />### Angle (\(\theta\)) = \(30^\circ\), Time (\(t\)) = 1 second, Gravity (\(g\)) = 9.8 m/s\(^2\). We need to find the initial velocity (\(v_0\)).<br />## Step 2: Formulate the vertical motion equation <br />### The vertical component of the initial velocity is \(v_0 \sin(\theta)\). Use the formula \(v_{y} = v_0 \sin(\theta) - gt\).<br />## Step 3: Solve for initial velocity using kinematic equations<br />### At the top of the trajectory, the vertical velocity will be 0. We have \(v_0\sin(30^\circ) = g \cdot t/2\). Solve for \(v_0\).<br />\[<br />v_0\sin(30^\circ) = 9.8 \cdot \frac{1}{2}<br />\]<br />\[<br />v_0 \cdot \frac{1}{2} = 4.9<br />\]<br />\[<br />v_0 = 9.8<br />\]<br />## Step 4: Calculate total initial velocity <br />### \(v_0 = \frac{2 \cdot 4.9}{ \sin(30^\circ)} = 20 m/s\)
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