Question

A train travelling at 18m/s accelerates uniformly at 2m/s^2 for 6 seconds . Calculate the final speed of the train.

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WynonaElite · Tutor for 8 years

Answer

<p> The final speed 'v' would thus be calculated as \(v = u + at = 18 \mathrm{~m} / \mathrm{s} + 2 \mathrm{~m} / \mathrm{s}^2*6s = 30 \mathrm{~m} / \mathrm{s}\).

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<p> This is a simple problem of motion that can be worked out using the formula for speed in uniformly accelerated rectilinear motion, which is v = u + at. Here, 'v' is the final velocity or speed, 'u' is the initial velociry or speed, 'a' is the acceleration, and 't' is the time of travel. In this problem, the initial speed 'u' is given as \(18 \mathrm{~m} / \mathrm{s} \), the acceleration 'a' is \( 2 \mathrm{~m} / \mathrm{s}^{2} \), and the time 't' is 6 seconds.</p>

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