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Question 20 The half-life of the radioisotope strontium -90 is 29 years. How much of a 10 .0 g sample will remain after 87 years? 1.54g 1.23g 1.25g 2.03g Points 3

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Question 20 The half-life of the radioisotope strontium -90 is 29 years. How much of a 10 .0 g sample will remain after 87 years? 1.54g 1.23g 1.25g 2.03g Points 3

Question 20 The half-life of the radioisotope strontium -90 is 29 years. How much of a 10 .0 g sample will remain after 87 years? 1.54g 1.23g 1.25g 2.03g Points 3

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KristinaProfessional · Tutor for 6 years

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### 1.25 g

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## Step 1: Determine the number of half-lives<br />### We need to find out how many half-lives have passed in 87 years. We do this by dividing the total time elapsed (87 years) by the length of each half-life (29 years).<br />\[\frac{87 \text{ years}}{29 \text{ years/half-life}} = 3 \text{ half-lives}\]<br /><br />## Step 2: Calculate the remaining amount after the given half-lives<br />### After 3 half-lives, the remaining amount of the sample can be calculated by halving the initial amount 3 times.<br />\[10.0 \text{ g} \times \left(\frac{1}{2}\right)^3 = 10.0 \text{ g} \times \frac{1}{8} = 1.25 \text{ g}\]<br /><br />#
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