Home
/
Physics
/
4. From the question #3, A 28 .5g of iron shot is added to a graduated cylinder containing 45 .50mL of water . The water level rises to the 49.10mL mark, calculate the density of iron. Typearesponse

Question

4. From the question #3, A 28 .5g of iron shot
is added to a graduated cylinder
containing 45 .50mL of water . The water
level rises to the 49.10mL mark, calculate
the density of iron.
Typearesponse

4. From the question #3, A 28 .5g of iron shot is added to a graduated cylinder containing 45 .50mL of water . The water level rises to the 49.10mL mark, calculate the density of iron. Typearesponse

expert verifiedVerification of experts

Answer

4.5133 Voting
avatar
MagnusElite · Tutor for 8 years

Answer

The density of the iron shot is 7.92g/mL.

Explain

## Step 1: Identify the given quantities<br />In this problem, we are given the mass (m) of the iron shot, which is 28.5g. We are also given the initial volume of water in the graduated cylinder, which is 45.50mL, and the final volume of water after the iron shot is added, which is 49.10mL.<br /><br />## Step 2: Calculate the volume of the iron shot<br />The volume (V) of the iron shot can be calculated by the displacement method. It is equal to the change in water level when the iron shot is added. In this case, the water level increases from 45.50mL to 49.10mL. Therefore, the volume displaced by the iron shot is \(49.10mL - 45.50mL = 3.60mL\).<br /><br />## Step 3: Calculate the density of the iron shot<br />The density (D) of a material is calculated using the formula:<br /><br />### **Density = mass/volume**<br /><br />Using the values we have, the density of the iron shot is \(D = m/V = 28.5g / 3.60mL = 7.92g/mL\).
Click to rate:

Hot Questions

More x