6 Fill in the missing values in the table below and suggest a device in each case. Device & Efficiency in % & Input & Useful output & & 140 mathrm(~kJ) & 135 mathrm(~kJ) & 17 & & 45 mathrm(~J) & 36 & 12 mathrm(MW) &

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6 Fill in the missing values in the table below and suggest a device in each case. Device & Efficiency in % & Input & Useful output & & 140 mathrm(~kJ) & 135 mathrm(~kJ) & 17 & & 45 mathrm(~J) & 36 & 12 mathrm(MW) &

Answer 1

### \begin{array}{|c|c|c|c|}<br\ />\hline\ Device\ &\ Efficiency\ in\ \%\ &\ Input\ &\ Useful\ output\ \\<br\ />\hline\ Electric\ Motor\ &\ 96.43\ &\ 140\ \mathrm{~kJ}\ &\ 135\ \mathrm{~kJ}\ \\<br\ />\hline\ Incandescent\ Light\ Bulb\ &\ 17\ &\ 264.71\ \mathrm{~J}\ &\ 45\ \mathrm{~J}\ \\<br\ />\hline\ Gas\ Turbine\ &\ 36\ &\ 12\ \mathrm{MW}\ &\ 4.32\ \mathrm{MW}\ \\<br\ />\hline<br\ />\end{array}

Answer 2

## Step 1: Calculate Efficiency for the First Row ### Efficiency is calculated using the formula: \[\text{Efficiency} = \left( \frac{\text{Useful Output}}{\text{Input}} \right) \times 100\] Given Input = \(140 \, \mathrm{kJ}\) and Useful Output = \(135 \, \mathrm{kJ}\): \[\text{Efficiency} = \left( \frac{135 \, \mathrm{kJ}}{140 \, \mathrm{kJ}} \right) \times 100 \approx 96.43\%\] ## Step 2: Calculate Input for the Second Row ### Rearrange the efficiency formula to solve for Input: \[\text{Input} = \frac{\text{Useful Output}}{\text{Efficiency}} \times 100\] Given Efficiency = 17% and Useful Output = \(45 \, \mathrm{J}\): \[\text{Input} = \frac{45 \, \mathrm{J}}{17} \times 100 \approx 264.71 \, \mathrm{J}\] ## Step 3: Calculate Useful Output for the Third Row ### Rearrange the efficiency formula to solve for Useful Output: \[\text{Useful Output} = \text{Input} \times \left( \frac{\text{Efficiency}}{100} \right)\] Given Efficiency = 36% and Input = \(12 \, \mathrm{MW}\): \[\text{Useful Output} = 12 \, \mathrm{MW} \times \left( \frac{36}{100} \right) = 4.32 \, \mathrm{MW}\] ## Step 4: Suggest Devices for Each Case ### Based on the calculated efficiencies and typical device efficiencies: 1. First Row: A highly efficient device such as an electric motor. 2. Second Row: A low-efficiency device such as an incandescent light bulb. 3. Third Row: A moderately efficient device such as a gas turbine.

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6 Fill in the missing values in the table below and suggest a device in each case. Device & Efficiency in % & Input & Useful output & & 140 mathrm(~kJ) & 135 mathrm(~kJ) & 17 & & 45 mathrm(~J) & 36 & 12 mathrm(MW) &

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