A lift that weighs 300N moves a man with a weight of 950N upwards by 12m. How much work is done to move the lift this height?

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A lift that weighs 300N moves a man with a weight of 950N upwards by 12m. How much work is done to move the lift this height?

Answer 1

The work done to move the lift this height is \( 15,000 \mathrm{~J} \).

Answer 2

## Step 1: The first step in solving this problem is to understand the concept of work done in physics. The work done on an object is equivalent to the force applied to it multiplied by the displacement it moves while the force is applied. This can be represented mathematically as \( W = F \cdot d \cdot \cos \theta \), where \( W \) is the work done, \( F \) is the force applied, \( d \) is the displacement, and \( \theta \) is the angle between the force and the displacement. ## Step 2: In this problem, the force is the total weight of the lift and the man, which is \( 300 \mathrm{~N} + 950 \mathrm{~N} = 1250 \mathrm{~N} \). The displacement is the distance the lift moves upwards, which is \( 12 \mathrm{~m} \). The angle \( \theta \) is \( 0^\circ \) because the force and the displacement are in the same direction (upwards). ## Step 3: Substitute the values of \( F \), \( d \), and \( \theta \) into the formula for work done. ### \( W = F \cdot d \cdot \cos \theta = 1250 \mathrm{~N} \cdot 12 \mathrm{~m} \cdot \cos 0^\circ \) ## Step 4: Calculate the work done. ### \( W = 1250 \mathrm{~N} \cdot 12 \mathrm{~m} = 15,000 \mathrm{~J} \)

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A lift that weighs 300N moves a man with a weight of 950N upwards by 12m. How much work is done to move the lift this height?

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