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A 50.0-kg object has an eastward momentum of 350kgcdot m/s The object encounters an eastward impulse of 100Ncdot s What is the magnitude of the final momentum of the object? 7.0kgcdot m/s 9.0kgcdot m/s 450kgcdot m/s 250kgcdot m/s

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A 50.0-kg object has an eastward momentum of 350kgcdot m/s The object encounters an eastward impulse of 100Ncdot s What is the magnitude of the final momentum of the object? 7.0kgcdot m/s 9.0kgcdot m/s 450kgcdot m/s 250kgcdot m/s

A 50.0-kg object has an eastward momentum of 350kgcdot m/s The object encounters an eastward impulse of 100Ncdot s What is the magnitude of the final momentum of the object? 7.0kgcdot m/s 9.0kgcdot m/s 450kgcdot m/s 250kgcdot m/s

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EmiliaElite · Tutor for 8 years

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\(450 kg\cdot m/s\)

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## Step1: <br />The problem is about the principle of impulse and momentum in physics. The initial momentum of the object is given as eastward with a magnitude of \(350 kg\cdot m/s\). The impulse the object receives is also in the eastward direction with a magnitude of \(100 N\cdot s\).<br /><br />## Step2: <br />The general formula that relates momentum (p) and impulse (J) is as follows:<br /><br />### \(\Delta p = J\)<br /><br />In this formula, \(\Delta p\) represents the change in momentum which is equal to the applied impulse. The final momentum we seek in this problem can be thought as initial momentum (start momentum, in our case it's eastwards of \(350 kg\cdot m/s\)) + any change in cumulative forces (action and reaction pairs in which our object gets affected indirectly).<br /><br />## Step3: <br />In our scenario, we need the impulse towards east which our object is exposed to. This formula (initial momentum + change in momentum) can create the following equation:<br /><br />### Final momentum = \(350 kg\cdot m/s + 100 N\cdot s\)<br /><br />This equation will yield us the value for the final momentum.
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