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What would be the total resistance of a series circuit containing five resistors each having a resistance of 10Omega a 5Omega b 100 C 50Omega d 500Omega

Question

What would be the total resistance of a series circuit containing five resistors each having a resistance of
10Omega 
a
5Omega 
b
100
C
50Omega 
d
500Omega

What would be the total resistance of a series circuit containing five resistors each having a resistance of 10Omega a 5Omega b 100 C 50Omega d 500Omega

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YancyMaster · Tutor for 5 years

Answer

Based on our formula and calculations, option "c", which is \(50 \, \Omega\) is the correct choice for the total resistance of a series circuit with five resistors each having a resistance of \(10 \, \Omega\). So, the answer is (c) \( 50 \, \Omega \).

Explain

## Step 1: <br />The given question asks us to find the total resistance of a series circuit containing five resistors with each resistor having a resistance of \(10 \, \Omega \). <br />In a series circuit, the total resistance \((R_T) \) is equal to the sum of each individual resistance as derived from Ohm's law.<br /><br />### The formula used to find the total resistance (R_T) is:<br /> **\(R_T = R_1 + R_2 + R_3 + R_4 + R_5\)**<br /><br />Where each of \(R_1, R_2, R_3, R_4\) and \(R_5\) is a resistor in the circuit. <br /><br />## Step 2:<br />Knowing that each individual resistor (\(R_1, R_2, R_3, R_4, R_5\)) has the resistance of \(10 \, \Omega \), substituting this value into our total resistance formula gives:<br /><br /> **\(R_T = 10 + 10 + 10 + 10 + 10\)**<br /><br />## Step 3:<br />On calculation, we obtain a total resistance of - <br /><br /> **\(R_T= 50 \, \Omega \)**<br /><br />Our Objective therefore is to find this total resistance of \( 50 \, \Omega \) in our multiple-choice options.
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