A box in the shape of a cuboid is placed on a horizontal floor. The box exerts a force of 180 newtons on the floor. The box exerts a pressure of 187.5newtons/m^2 on the floor. The face in contact with the floor is a rectangle of length 1.2 metres and width z metres. Work out the value of x. pressure=(force)/(area) (3 marks) 8x= square

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A box in the shape of a cuboid is placed on a horizontal floor. The box exerts a force of 180 newtons on the floor. The box exerts a pressure of 187.5newtons/m^2 on the floor. The face in contact with the floor is a rectangle of length 1.2 metres and width z metres. Work out the value of x. pressure=(force)/(area) (3 marks) 8x= square

Answer 1

Now from the calculations, I find that the value of 'x', the width of the box, is x = 1.2 \( \mathrm{m} \).

Answer 2

## Step1: Firstly, identify the values given in the problem, \(F = 180N\) the force, \(P = 187.5 N/m^{2}\) the pressure, and the box length "length" = 1.2m. We are asked to find the width 'x' of the box. ## Step2: Next, realize that we can utilize the pressure formula, \(P = \frac{F}{A} \), where \( P \) is pressure, \( F \) is force, and \( A \) is Area. Here, language_week is 'x', so, the area will be length * width = 1.2m * x ## Step3: Solve for 'x' by substituting given values in the formula. We get \( 187.5 N/m^{2}=\frac{180N}{1.2m * x} \) ## Step4: To solve the above equation, reconcept it as \( x=\frac{180N}{1.2m * 187.5 N/m^{2}}\) ## Step5: Perform the required calculation.

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