The numbers in this sequence increase by 13 each time. Find the missing numbers. boxed (92 boxed (105) 118 square boxed (144) square )

Question

Question

The numbers in this sequence increase by 13 each time. Find the missing numbers. boxed (92 boxed (105) 118 square boxed (144) square )

Answer 1

The missing numbers are \( 79, 118, \) and \( 144 \)

Answer 2

## Step 1: To find the missing numbers in an arithmetical sequence (where each term increase with a constant number), we use the formula: ### \( a[n] = a[1] + (n - 1) \cdot d \) where, - \( a[1] \) is the first term, - \( d \) is the difference between consecutive terms, - \( n \) is the position of the term in the sequence. In our case, the difference \( d \) between consecutive terms is given as 13. ## Step 2: Calculate the first missing number: From the context of the request, we can calculate the third element in the sequence named \( a[1] \) which will be: ### \( \text{first number} = 92 - 13 = 79 \) ## Step 3: Calculate the second missing number: This will come 4 places after 79, so n = 4 ### \( \text{Next Missing Number} = 79 + (4 -1) \times 13 = 79 + 3 \times 13 = 118 \) ## Step 4: Find the last missing number in the sequence, again placing it in the correct place \( n = 6 \) ### \( \text{Last Missing Number} = 79 + (6 - 1) \times 13 = 79 + 5 \times 13 = 144 \)

Question

The numbers in this sequence increase by 13 each time. Find the missing numbers. boxed (92 boxed (105) 118 square boxed (144) square )

Answer

Answer

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