At th e sta rt of an ex perim ent, s ome chemic als ha d a ma ss of 84g, roun ded t o 2 sig nifica nt fig ures. During the ex perim ent, th e mas s of the che mical s decr ease d by 6.2 g, roun ded t o 2 sig nifica nt fig ures. Calculat e the lo wer a nd uppe r bou nds of the mass of th e chem Icals a t the end o f the e xperime nt.

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At th e sta rt of an ex perim ent, s ome chemic als ha d a ma ss of 84g, roun ded t o 2 sig nifica nt fig ures. During the ex perim ent, th e mas s of the che mical s decr ease d by 6.2 g, roun ded t o 2 sig nifica nt fig ures. Calculat e the lo wer a nd uppe r bou nds of the mass of th e chem Icals a t the end o f the e xperime nt.

Answer 1

The lower and upper bounds of the mass of the chemicals at the end of the experiment are \(77.25\)g and \(78.35\)g, respectively.

Answer 2

## Step 1: Determine the bounds for the initial mass. ### **The initial mass is given as 84g, rounded to 2 significant figures.** - Lower bound: \(83.5\)g (since \(83.5\)g rounds up to \(84\)g) - Upper bound: \(84.5\)g (since \(84.5\)g rounds down to \(84\)g) ## Step 2: Determine the bounds for the decrease in mass. ### **The decrease in mass is given as 6.2g, rounded to 2 significant figures.** - Lower bound: \(6.15\)g (since \(6.15\)g rounds up to \(6.2\)g) - Upper bound: \(6.25\)g (since \(6.25\)g rounds down to \(6.2\)g) ## Step 3: Calculate the bounds for the final mass. ### **To find the final mass, subtract the bounds of the decrease in mass from the bounds of the initial mass.** - Lower bound of final mass: \(83.5\)g - \(6.25\)g = \(77.25\)g - Upper bound of final mass: \(84.5\)g - \(6.15\)g = \(78.35\)g

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