m_(1)v_(1)+m_(2)v_(2)=m_(1)v_(1)'+m_(2)v_(2)' What is the velocity of the 10 kg ball after the collision? .8m/s 1.2m/s .5m/s 2m/s

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m_(1)v_(1)+m_(2)v_(2)=m_(1)v_(1)'+m_(2)v_(2)' What is the velocity of the 10 kg ball after the collision? .8m/s 1.2m/s .5m/s 2m/s

Answer 1

To solve this problem, we need to apply the principle of conservation of momentum. The equation provided is the conservation of momentum equation for a two-body system:\[m_{1}v_{1} + m_{2}v_{2} = m_{1}v_{1}^{\prime} + m_{2}v_{2}^{\prime}\]where:- \(m_{1}\) and \(m_{2}\) are the masses of the two objects before the collision.- \(v_{1}\) and \(v_{2}\) are the velocities of the two objects before the collision.- \(v_{1}^{\prime}\) and \(v_{2}^{\prime}\) are the velocities of the two objects after the collision.From the picture details, we know that:- \(m_{1} = 5\) kg (mass of the blue ball)- \(v_{1} = 10\) m/s (velocity of the blue ball)- \(m_{2}\) is the mass of the second ball, which is \(10\) kg.- \(v_{2}\) is the velocity of the second ball before the collision, which is not given but we can assume it to be 0 m/s if the ball is initially at rest.We are asked to find \(v_{2}^{\prime}\), the velocity of the \(10\) kg ball after the collision.Let's assume that the second ball is initially at rest, so \(v_{2} = 0\) m/s.Using the conservation of momentum equation:\[m_{1}v_{1} + m_{2}v_{2} = m_{1}v_{1}^{\prime} + m_{2}v_{2}^{\prime}\]Substitute the known values:\[(5 \text{ kg})(10 \text{ m/s}) + (10 \text{ kg})(0 \text{ m/s}) = (5 \text{ kg})v_{1}^{\prime} + (10 \text{ kg})v_{2}^{\prime}\]Since we don't have the value of \(v_{1}^{\prime}\), we cannot solve this equation directly for \(v_{2}^{\prime}\). We need additional information to find the final velocity of the \(10\) kg ball. This could be the type of collision (elastic or inelastic), or the final velocity of the 5 kg ball after the collision.Without this additional information, we cannot determine the correct answer from the options provided. Please provide the missing information or clarify the conditions of the collision so that we can proceed with the calculation.

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m_(1)v_(1)+m_(2)v_(2)=m_(1)v_(1)'+m_(2)v_(2)' What is the velocity of the 10 kg ball after the collision? .8m/s 1.2m/s .5m/s 2m/s

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