Round to 2 decimal places when needed. The velocity of an object dropped from a height of his given by the function V= sqrt (2gh) where gi is the gravitational constant, 32.2ft/s^2 . If an object is dropped from the roof of a building that is 1000 it tall, how fast is it traveling when it hits the ground?

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Round to 2 decimal places when needed. The velocity of an object dropped from a height of his given by the function V= sqrt (2gh) where gi is the gravitational constant, 32.2ft/s^2 . If an object is dropped from the roof of a building that is 1000 it tall, how fast is it traveling when it hits the ground?

Answer 1

The velocity of the object when it hits the ground is approximately 80.50 ft/s.

Answer 2

## Step 1: We are given the formula for the velocity of an object dropped from a height \(h\), which is \(V = \sqrt{2gh}\), where \(g\) is the gravitational constant and \(h\) is the height from which the object is dropped. ## Step 2: We are given that \(h = 1000\) ft and \(g = 32.2\) ft/s². We need to substitute these values into the formula to find the velocity \(V\) when the object hits the ground. ## Step 3: Substitute the given values into the formula, we get \(V = \sqrt{2*32.2*1000}\). ## Step 4: Perform the multiplication and square root operations to find the value of \(V\). ## Step 5: Round the calculated value to two decimal places as instructed in the question.

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