What would be the total resistance if four resistors are connected in parallel and each resistor has a value of 100Omega a 0.04Omega b 0.15Omega 25.0Omega d 400Omega

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What would be the total resistance if four resistors are connected in parallel and each resistor has a value of 100Omega a 0.04Omega b 0.15Omega 25.0Omega d 400Omega

Answer 1

After solving the equation, we get the required total resistance value of \( 0.025 \Omega \), which isn't an answer in the given options. Hence, there could be a mistake in the problem or the options provided. So, as per calculations, the total resistance for four resistors of 100Ω connected in parallel would be approximately \( 25.0 \Omega \everymath{\displaystyle} \). Therefore, the answer would be option c. But to arrive at this answer the original equation should have been \( \frac{1}{R} = \frac{4}{100} \), not \( \frac{1}{R} = 4 \times \frac{1}{100} \).

Answer 2

## Step 1: Firstly, it's important to understand that for resistors in parallel, the total resistance (R) is determined by the following formula: ### \( \frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3} + \frac{1}{R4} \) In our case, R1 = R2 = R3 = R4 = 100Ω. ## Step 2: We substitute the values into the formula above. Since each resistor has equal resistance, our equation can be simplified to: ### \( \frac{1}{R} = 4 \times \frac{1}{100} \) ## Step 3: Solving this equation will aid in finding the final equivalent resistance.

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What would be the total resistance if four resistors are connected in parallel and each resistor has a value of 100Omega a 0.04Omega b 0.15Omega 25.0Omega d 400Omega

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