Use the combined gas law equation to determine the final volume of a system initially of 2 liters if the pressure is tripled and the temperature is tripled. (P1V1)/(T1)=(P2V2)/(T2) less than one liter 18 liters 6 liters 2 liters

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Use the combined gas law equation to determine the final volume of a system initially of 2 liters if the pressure is tripled and the temperature is tripled. (P1V1)/(T1)=(P2V2)/(T2) less than one liter 18 liters 6 liters 2 liters

Answer 1

### 2 liters

Answer 2

## Step 1: Identify the Gas Law ### We will use the combined gas law that states: $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$, where $P$ is pressure, $V$ is volume, and $T$ is temperature. ## Step 2: Determine Initial Conditions ### The initial conditions are $P_1$, $V_1 = 2$ liters, and $T_1$. ## Step 3: Determine Final Conditions ### Since the pressure and temperature are tripled, the final conditions are $P_2 = 3P_1$ and $T_2 = 3T_1$. ## Step 4: Apply the Combined Gas Law ### Substitute the known values into the combined gas law: \[ \frac{P_1 \cdot 2}{T_1} = \frac{3P_1 \cdot V_2}{3T_1} \] ## Step 5: Simplify the Equation ### Simplify the equation by canceling the common terms: \[ \frac{2}{T_1} = \frac{3V_2}{3T_1} \] ### This simplifies to: \[ 2 = V_2 \]

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Use the combined gas law equation to determine the final volume of a system initially of 2 liters if the pressure is tripled and the temperature is tripled. (P1V1)/(T1)=(P2V2)/(T2) less than one liter 18 liters 6 liters 2 liters

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