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3 Calculate the en ergy ne eded t O inc reas e the t emper ature of 2 L of o il in a fry er from a 10^circ C to 210^circ C . The sp ecific heat c apac S 2kJ/^circ C/kg and the de nsity of oil is 0.5kg/L . Re member the equation for chang e in internal energy. E=mcDelta T 2 D Substitute the values in. E=(2times 0.5)times 2times (210-10) b-Write the result with the correct unit. E=1kJ

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3 Calculate the en ergy ne eded t O inc reas e the t emper ature of 2 L of o il in a fry er from a 10^circ C to 210^circ C . The sp ecific heat c apac S 2kJ/^circ C/kg and the de nsity of oil is 0.5kg/L . Re member the equation for chang e in internal energy. E=mcDelta T 2 D Substitute the values in. E=(2times 0.5)times 2times (210-10) b-Write the result with the correct unit. E=1kJ

3 Calculate the en ergy ne eded t O inc reas e the t emper ature of 2 L of o il in a fry er from a 10^circ C to 210^circ C . The sp ecific heat c apac S 2kJ/^circ C/kg and the de nsity of oil is 0.5kg/L . Re member the equation for chang e in internal energy. E=mcDelta T 2 D Substitute the values in. E=(2times 0.5)times 2times (210-10) b-Write the result with the correct unit. E=1kJ

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CeciliaMaster · Tutor for 5 years

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<p> Firstly we substitute these numbers into the first equation, spreading out the result:<br />\[E = 1 kg * 2 kJ \frac {1 (kg * ^{\circ}\mathrm{C})}{2L} * 200 ^{\circ}\mathrm{C}\]. Remember to only keep significant digits, we find \[E = 400 kJ \]</p>

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<p> Here we are asked to find the energy required to heat up a certain amount of oil. We can use the relationship for heat transfer to an object \(E=mc\Delta T\), where \(E\) is the heat transfer, \(m\) the mass of the object, \(c\) the specific heat capacity, and \(\Delta T\) the temperature change.<br />The question tells us we have 2.0 liters of oil. We will be raising its development temperature from its original warmth of \(10^{\circ} \mathrm{C}\) to \(210^{\circ} \mathrm{C}\), as in the question; we translate it to a change in temperature \(\Delta T\) of \(200^{\circ} \mathrm{C}\). We also are given the specific heat capacity of oil \((2.0 \frac{kJ}{k.g^{\circ} \mathrm{C}})\). Also given is the dens_estimatorsity of oil, which we can use to find the mass given its volume. Since density \(ρ = \frac{mass}{volume}\)), then also \(mass = ρ * volume\). According to this respecter, the mass of \(2L\) of oil is \(2 * 0.5 kg (mass) = 1 kg\).</p>
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