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A train departs from its station at a constant acceleration of 5m/s^2 What is the speed of the train after 20 s? a 0.4m/s b 100m/s C -100m/s d 4m/s

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A train departs from its station at a constant acceleration of 5m/s^2 What is the speed of the train after 20 s? a 0.4m/s b 100m/s C -100m/s d 4m/s

A train departs from its station at a constant acceleration of 5m/s^2 What is the speed of the train after 20 s? a 0.4m/s b 100m/s C -100m/s d 4m/s

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GeraldProfessional · Tutor for 6 years

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### b. $100 \, \text{m/s}$

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## Step1: Identify the given values<br />### The problem provides the acceleration \(a = 5 \, \text{m/s}^2\) and the time \(t = 20 \, \text{s}\).<br />## Step2: Use the formula for final velocity<br />### The formula for final velocity \(v\) under constant acceleration is \(v = u + at\), where \(u\) is the initial velocity. Since the train starts from rest, \(u = 0\).<br />## Step3: Substitute the values into the formula<br />### Substituting \(u = 0\), \(a = 5 \, \text{m/s}^2\), and \(t = 20 \, \text{s}\) into the formula \(v = 0 + 5 \times 20\).<br />## Step4: Calculate the final velocity<br />### Performing the calculation: \(v = 5 \times 20 = 100 \, \text{m/s}\).
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