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9. If "B"=50 pounds, what would box "A" have to weigh for this lever to be in balance? a. MomentofB= b Moment of A= A= c. Weight of A= A=

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9. If "B"=50 pounds, what would box "A" have to weigh for this lever to be in balance? a. MomentofB= b Moment of A= A= c. Weight of A= A=

9. If "B"=50 pounds, what would box "A" have to weigh for this lever to be in balance? a. MomentofB= b Moment of A= A= c. Weight of A= A=

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YvetteElite · Tutor for 8 years

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a. Moment of B = \( 50 \text{ pounds} \times \text{distance from pivot} \)<br /><br />b. Moment of A = \( \text{Weight of A} \times \text{distance from pivot} \)<br /><br />c. Weight of A = \( \frac{\text{Moment of B}}{\text{distance from pivot}} \)<br /><br />To find the exact weight of A, we need the distance from the pivot for both A and B. If the distances are equal, then Weight of A = 50 pounds. If not, use the formula in (c) with the given distances.

Explain

This problem involves understanding the concept of moments in physics, specifically the principle of moments (or torque) for a lever in equilibrium. The moment is calculated as the product of the force (weight) and the distance from the pivot. For the lever to be balanced, the moments on both sides must be equal.
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