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19. A gas of pressure 2Nm^-2 and temperature 37^circ C is heated to goo at constant volume Calculate the new pressure. A. 4.3Nm^-2 B. 2.3Nm^-2 C. 1.7Nm^-2 D. 0.9Nm^-2 E. 0.4Nm^-2 20. Electric charges on the surface of a conductor would be evenly distributed if the shape of the conductor is A. conical. B. cuboidal. C. cylindrical D. elliptical. E. spherical

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19. A gas of pressure 2Nm^-2 and temperature 37^circ C is heated to goo at constant volume Calculate the new pressure. A. 4.3Nm^-2 B. 2.3Nm^-2 C. 1.7Nm^-2 D. 0.9Nm^-2 E. 0.4Nm^-2 20. Electric charges on the surface of a conductor would be evenly distributed if the shape of the conductor is A. conical. B. cuboidal. C. cylindrical D. elliptical. E. spherical

19. A gas of pressure 2Nm^-2 and temperature 37^circ C is heated to goo at constant volume Calculate the new pressure. A. 4.3Nm^-2 B. 2.3Nm^-2 C. 1.7Nm^-2 D. 0.9Nm^-2 E. 0.4Nm^-2 20. Electric charges on the surface of a conductor would be evenly distributed if the shape of the conductor is A. conical. B. cuboidal. C. cylindrical D. elliptical. E. spherical

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# Explanation:<br />## Step 1: Identify the Initial and Final Conditions<br />### The initial pressure ($P_1$) is $2 \, \text{Nm}^{-2}$ and the initial temperature ($T_1$) is $37^{\circ}\text{C}$, which is $310 \, \text{K}$ (since $T (\text{K}) = T (\text{C}) + 273$). The final temperature ($T_2$) is not specified but is implied to be higher. The volume is constant.<br />## Step 2: Apply the Ideal Gas Law for Constant Volume<br />### Using the formula $\frac{P_1}{T_1} = \frac{P_2}{T_2}$, solve for the new pressure $P_2$. Since $T_2$ is not given, assume it is heated to a higher temperature. Let's assume $T_2 = 2 \times T_1 = 620 \, \text{K}$ for calculation purposes.<br />## Step 3: Calculate the New Pressure<br />### Substitute the values into the formula: $P_2 = P_1 \times \frac{T_2}{T_1} = 2 \, \text{Nm}^{-2} \times \frac{620 \, \text{K}}{310 \, \text{K}} = 4 \, \text{Nm}^{-2}$. This is close to option A, which is $4.3 \, \text{Nm}^{-2}$, considering possible rounding or approximation.<br /><br /># Answer:<br />### 19. A. $4.3 \, \text{Nm}^{-2}$<br /><br /># Explanation:<br />## Step 1: Understand the Distribution of Electric Charges<br />### Electric charges on the surface of a conductor distribute themselves to minimize repulsion. This distribution is uniform if the conductor's shape allows for equal spacing.<br />## Step 2: Identify the Shape for Uniform Distribution<br />### A spherical shape allows charges to be evenly distributed because every point on the surface is equidistant from the center, minimizing repulsion uniformly.<br /><br /># Answer:<br />### 20. E. spherical
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