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Calculate the heat energy transferred if the temperature of 600 g of lead is raised from 20^circ C to 100^circ C

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Calculate the heat energy transferred if the temperature of 600 g of lead is raised
from 20^circ C to 100^circ C

Calculate the heat energy transferred if the temperature of 600 g of lead is raised from 20^circ C to 100^circ C

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HarrisonMaster · Tutor for 5 years

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The heat energy transferred to raise the temperature of 600 g of lead from \(20^{\circ}C\) to \(100^{\circ}C\) is 6192 joules.

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## Step 1:<br />The formula for calculating the amount of heat (\(Q\)) required to change the temperature of a substance is given by:<br />### \(Q = mc\Delta T\)<br />where:<br />- \(m\) is the mass of the substance,<br />- \(c\) is the specific heat of the substance, and<br />- \(\Delta T\) is the change in temperature.<br /><br />## Step 2:<br />For lead (Pb), the specific heat at constant pressure (\(C_p\)) is 0.129 J/(g·℃). The mass of lead (\(m\)) is 600 g, and the temperature change (\(\Delta T\)) is from \(20^{\circ}C\) to \(100^{\circ}C\).<br /><br />## Step 3:<br />Calculate the temperature change (\(\Delta T\)):<br />### \(\Delta T = T_{final} - T_{initial} = 100^{\circ}C - 20^{\circ}C = 80^{\circ}C\)<br /><br />## Step 4:<br />Substitute the values of \(m\), \(c\), and \(\Delta T\) into the formula \(Q = mc\Delta T\):<br />### \(Q = 600 \, \text{g} \times 0.129 \, \text{J/(g·℃)} \times 80^{\circ}C\)<br /><br />## Step 5:<br />Calculate the heat required (\(Q\)) using the substituted values:<br />### \(Q = 600 \times 0.129 \times 80 = 6192 \, \text{J}\)
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