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pressure=(force)/(area) A box is put on a table. The face of the box in contact with the table is in the shape of a rectangle, 2 m by 1.25 m. The pressure on the table due to the box is 42newtons/m^2 Work out the kerted by the box on the table.

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pressure=(force)/(area) A box is put on a table. The face of the box in contact with the table is in the shape of a rectangle, 2 m by 1.25 m. The pressure on the table due to the box is 42newtons/m^2 Work out the kerted by the box on the table.

pressure=(force)/(area) A box is put on a table. The face of the box in contact with the table is in the shape of a rectangle, 2 m by 1.25 m. The pressure on the table due to the box is 42newtons/m^2 Work out the kerted by the box on the table.

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HarlowMaster · Tutor for 5 years

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105 N

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<br />1. The issue here requires us to use the formula of pressure \( P = \frac{F}{A} \), where \( P \) is the pressure, \( F \) is the force, and \( A \) is the area, and solve it to get the force \( F \). In this case, we have pressure \( P = 42 \text{ N/m}^2 \), and the area of the face of the box that contacts with the table \( A = 2m \times 1.25m = 2.5m^2 \).<br />2. After rearranging the formula, we got \( F = P \times A \).<br />3. Then substituting the values into the formula, we have \( F = 42 \text{ N/m}^2 \times 2.5m^2 \).<br />4. With the calculation, the force exerted by the box on the table will be \( F = 105 \text{ N} \).<br /><br />Therefore, the box exerts a force of 105 N on the table.
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