Home
/
Physics
/
If the SPECIFIC LATENT HEAT of a substance is 200J/kg and the ENERGY ( required for a CHANGE of STATE is 40 what is the MASS m of the substance? [CHECK the UNITS] E 40 m=(E)/(L)=(40)/(200)=0.2kg m L-200-0 E 40 m=(E)/(L)=(40)/(200)=0.2g m=I = L 200 m=(L)/(E)=(200)/(40)=5kg m=E = 40

Question

If the SPECIFIC LATENT HEAT of a substance is 200J/kg and the ENERGY ( required for a CHANGE of STATE is 40 what is the MASS m of the substance? [CHECK the UNITS] E 40 m=(E)/(L)=(40)/(200)=0.2kg m L-200-0 E 40 m=(E)/(L)=(40)/(200)=0.2g m=I = L 200 m=(L)/(E)=(200)/(40)=5kg m=E = 40

If the SPECIFIC LATENT HEAT of a substance is 200J/kg and the ENERGY ( required for a CHANGE of STATE is 40 what is the MASS m of the substance? [CHECK the UNITS] E 40 m=(E)/(L)=(40)/(200)=0.2kg m L-200-0 E 40 m=(E)/(L)=(40)/(200)=0.2g m=I = L 200 m=(L)/(E)=(200)/(40)=5kg m=E = 40

expert verifiedVerification of experts

Answer

4.3212 Voting
avatar
WesleyMaster · Tutor for 5 years

Answer

The mass of the substance is \(0.2 \, \mathrm{kg}\).

Explain

## Step 1:<br />The specific latent heat (\(L\)) is defined as the amount of heat energy required to change the state of a unit mass of a substance without changing its temperature. The formula relating the energy (\(E\)), mass (\(m\)), and specific latent heat (\(L\)) is given by:<br />### \[E = mL\]<br /><br />## Step 2:<br />From the question, we are given \(E = 40 \, \mathrm{J}\) and \(L = 200 \, \mathrm{J/kg}\). We need to solve for the mass (\(m\)). Rearranging the formula to solve for \(m\) gives us:<br />### \[m = \frac{E}{L}\]<br /><br />## Step 3:<br />Substituting the given values into the formula, we have:<br />### \[m = \frac{40 \, \mathrm{J}}{200 \, \mathrm{J/kg}}\]<br /><br />## Step 4:<br />Performing the division, we get:<br />### \[m = 0.2 \, \mathrm{kg}\]<br /><br />## Step 5:<br />Verify the units. The units of Joules (\(\mathrm{J}\)) cancel out, leaving the mass in kilograms (\(\mathrm{kg}\)).<br /><br />#
Click to rate:

Hot Questions

More x