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A student recorded the acceleration of a trolley down a ramp. 0.7m/s^2, 0.6m/s^2, 0.8m/s^2, 0.8m/s^2 Calculate the mean acceleration to 1 decimal place.

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A student recorded the acceleration of a trolley down a ramp. 0.7m/s^2, 0.6m/s^2, 0.8m/s^2, 0.8m/s^2 Calculate the mean acceleration to 1 decimal place.

A student recorded the acceleration of a trolley down a ramp. 0.7m/s^2, 0.6m/s^2, 0.8m/s^2, 0.8m/s^2 Calculate the mean acceleration to 1 decimal place.

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TildaElite · Tutor for 8 years

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Interpretation of Question:<br />The student has collected multiple readings of the acceleration of the trolley. The various readings are 0.7 m/s^2, 0.6 m/s^2, 0.8 m/s^2, and 0.8 m/s^2. To find the mean acceleration, we need to add all these readings and divide by the total number of readings.<br /><br />Approach:<br /><br />To calculate the mean (or average) of a set of numbers, follow these steps:<br /><br />1. Add up all the numbers.<br />2. Divide by the count of the numbers <br /><br />Solution Steps:<br /><br />1. First, let's add the given acceleration readings:<br />0.7 + 0.6 + 0.8 + 0.8 = 2.9 m/s^2 <br /><br />2. Count the number of readings. There are total 4 readings.<br /><br />3. Divide the sum by the number of readings:<br />2.9 m/s^2 / 4 = 0.725 m/s^2<br /><br />While answering the mean value is 0.725 m/s^2, but as the question asks for the answer till 1 decimal place, we need to round the answer. Rounding 0.725 to one decimal place gets us 0.7 m/s^2.<br /><br />So,<br /><br />The mean acceleration of the trolley down a ramp is 【Answer】: 0.7 m/s^2, to 1 decimal place.
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