Home
/
Physics
/
Assume the electron has a charge of -1.60times 10^-19C A 3.00 A appliance has 360 C of charge flow through it. Part A Operating duration How long was the appliance operating? Value square ? How many electrons passed through the appliance in this time ? Value square ? Units

Question

Assume the electron has a charge of -1.60times 10^-19C A 3.00 A appliance has 360 C of charge flow through it. Part A Operating duration How long was the appliance operating? Value square ? How many electrons passed through the appliance in this time ? Value square ? Units

Assume the electron has a charge of -1.60times 10^-19C A 3.00 A appliance has 360 C of charge flow through it. Part A Operating duration How long was the appliance operating? Value square ? How many electrons passed through the appliance in this time ? Value square ? Units

expert verifiedVerification of experts

Answer

4.5222 Voting
avatar
WinstonMaster · Tutor for 5 years

Answer

Let's break down the problem step-by-step to find the answers to both parts.<br /><br />### Part A: Operating Duration<br /><br />**Problem:** How long was the appliance operating if a 3.00 A appliance has 360 C of charge flow through it?<br /><br />**Step 1:** Understand the relationship between current (I), charge (Q), and time (t). The formula is:<br />\[I = \frac{Q}{t}\]<br /><br />**Step 2:** Rearrange the formula to solve for time (t):<br />\[t = \frac{Q}{I}\]<br /><br />**Step 3:** Substitute the given values into the formula:<br />\[Q = 360 \, \mathrm{C}\]<br />\[I = 3.00 \, \mathrm{A}\]<br /><br />\[t = \frac{360 \, \mathrm{C}}{3.00 \, \mathrm{A}}\]<br /><br />**Step 4:** Calculate the time:<br />\[t = 120 \, \mathrm{s}\]<br /><br />**Answer:** The appliance was operating for **120 seconds**.<br /><br />### Part B: Number of Electrons<br /><br />**Problem:** How many electrons passed through the appliance in this time?<br /><br />**Step 1:** Understand the relationship between charge (Q) and the number of electrons (n). The formula is:<br />\[Q = n \times e\]<br />where \(e\) is the charge of one electron (\(-1.60 \times 10^{-19} \, \mathrm{C}\)).<br /><br />**Step 2:** Rearrange the formula to solve for the number of electrons (n):<br />\[n = \frac{Q}{e}\]<br /><br />**Step 3:** Substitute the given values into the formula:<br />\[Q = 360 \, \mathrm{C}\]<br />\[e = -1.60 \times 10^{-19} \, \mathrm{C}\]<br /><br />\[n = \frac{360 \, \mathrm{C}}{1.60 \times 10^{-19} \, \mathrm{C}}\]<br /><br />**Step 4:** Calculate the number of electrons:<br />\[n = \frac{360}{1.60 \times 10^{-19}}\]<br />\[n = 2.25 \times 10^{21}\]<br /><br />**Answer:** The number of electrons that passed through the appliance is **\(2.25 \times 10^{21}\)**.<br /><br />### Summary<br />- **Part A:** The appliance was operating for **120 seconds**.<br />- **Part B:** The number of electrons that passed through the appliance is **\(2.25 \times 10^{21}\)**.
Click to rate:

Hot Questions

More x