Chemistry Homework Assistance
QuestionAI's chemistry problem solver is a middle school chemistry tutoring tool that summarises key chemical reactions and equations in real-time, featuring a robust learning system to empower even those with a weak foundation in chemistry.
You needn't fret over the elemental properties of the periodic table anymore. Here, you can effortlessly access chemical reactions and reaction principles corresponding to each element. Deductive reasoning from microscopic phenomena to discern the original structure of molecules and atoms is a research technique we staunchly champion.
- 5) Form the ionic bonds for: AlCl_(3) NaF Al_(2)O_(3) Li_(2)O
- Ammonia dissolves in water to give a solution. Will this solution be acidic or alkaline? Enter your answer
- Complete the sentence Choose the answer from the box. After one half-life , the activity of polonium -210 in the sample was __ Ba
- (e) The potassium sulfate solution has 0.86 g of potassium sulfate dissolved in 25cm^2 water. Calculate the mass of potassium sulfate needed to make 1.0dm^3 of solution. __
- a. -0.85V d. -2.37V b. +0.85V 8. Use the Table of Standard Reduction Potential stable,which species would reac with Al^3+ a. Pb only C. Fe and Pb b. Au^3- only d. Both Mg and k 9. The oxidation of hydrogen by oxygen is one of the most-used reactions in fuel. cell technology. The overall reaction which is given below,has a Delta G^circ value of -474kJ/mol What is the standard cell potential for this fuel cell? 2H_(2)(g)+O_(2)(g)arrow 2H_(2)O(l)Delta G^circ =-474kJ/mol a. 2.46V C. 1.23V b. 4.91 V d. 2.46 V 10. Which one of the following equations shows the relationship between standard Gibbs free energy and equilibrium constant? a. K=Delta G^circ C. Delta G^0=-RTlnK b. K=RTlnDelta G^circ d. Delta G^0=RTlnK 11. What is Delta G^circ for the following balanced reaction, if E^ast =+2.431V Al(s)+Fe^2ast (aq)arrow Al^3++Fe(l)E^ast =+2.431V a. -704kJ/mol b. +704kJ/mol C. -235kJ/mol d. -469kJ/mol 12. The value of E^ast for the following reaction is 1.10 V.What is the value of E_(ow) when the concentration of Cu^2+ is 1.0 M and the concentration of Zn^2+ is 0.025 M? Zn(s)+Cu^2+(aq)arrow Cu(s)+Zn^2+(aq)E^2=1.10 V.[Cu^2+]=1.0M [Zn^2+]=0.025M and a. 1.40 V b. 0.95 V C. 1.15V d. 0.80 V